A) 1.5
B) 1.1
C) 0.75
D) 0.55
Correct Answer: B
Solution :
Sol. (b) \[T.l=V\rho g\] or\[T.l=\pi {{r}^{2}}l\rho g\]or\[T=\pi {{r}^{2}}\rho g\] \[\therefore \]\[70\times {{10}^{-3}}=3.14\times {{r}^{2}}\times 8\times {{10}^{-3}}\times 9.8\] or\[{{r}^{2}}=\frac{70\times {{10}^{-3}}}{3.14\times 8\times {{10}^{-3}}\times 9.8}=0.28\] \[\therefore \]\[r=0.53\] \[\therefore \]Minimum diameter of the wire \[=2r=2\times 0.53\approx 1.1m\]You need to login to perform this action.
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