VMMC VMMC Medical Solved Paper-2014

  • question_answer
    The equation of a wave travelling on a string is \[y=4\sin \left[ \frac{\pi }{2}\left( 8t-\frac{x}{8} \right) \right],\] where x, y are in cm and t in second. The velocity of the wave is

    A) \[\text{64}\,\text{cm}{{\text{s}}^{\text{-1}}}\text{,}\] in-x direction

    B) \[32\,\text{cm}{{\text{s}}^{\text{-1}}}\text{,}\] in-x direction

    C) \[32\,\text{cm}{{\text{s}}^{\text{-1}}}\text{,}\] in +x direction

    D) \[36\,\text{cm}{{\text{s}}^{\text{-1}}}\text{,}\] in +x direction

    Correct Answer: D

    Solution :

    \[y=4\sin \left( 4\pi t-\frac{\pi x}{16} \right)\]where\[\omega =4\pi \]and\[k=\frac{2\pi }{\lambda }=\frac{\pi }{16}\]\[\Rightarrow \]\[v=\frac{\omega }{k}=64cm{{s}^{-1}},\]along + x direction.


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