A) \[10\mu F\]
B) \[15\mu F\]
C) \[20\mu F\]
D) \[25\mu F\]
Correct Answer: B
Solution :
Here, \[{{C}_{1}}\]and \[{{C}_{2}}\]are in series. Hence, their effective capacitance C" is given by \[\frac{1}{C'}=\frac{1}{{{C}_{1}}}=\frac{1}{{{C}_{2}}}\] \[\frac{1}{C'}=\frac{1}{20}+\frac{1}{20}\]\[\Rightarrow \]\[C'=10\mu F\] Similarly, \[\frac{1}{C''}=\frac{1}{{{C}_{3}}}+\frac{1}{{{C}_{4}}}\] \[\frac{1}{C''}=\frac{1}{10}+\frac{1}{10}\]\[\Rightarrow \]\[C''=5\mu F\] Now \[C'\]and \[C''\]are in parallel. Hence, resultant capacitance C will be \[C=C'+C''\] \[=10+5=15\mu F\]
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