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VMMC VMMC Medical Solved Paper-2014

  • question_answer
    The soave of a galvanometer of resistance \[100\Omega \]contains 25 divisions. It gives a deflection of one division on passing a current of \[4\times {{10}^{14}}A.\] The resistance in ohm to be added to it, so that it may become a voltmeter of range 2.5 V is

    A) 150   

    B) 170   

    C) 110                        

    D) 220

    Correct Answer: A

    Solution :

    The deflection of one division of galvanometer is given by the current \[=4\times {{10}^{-4}}A\]or the current sensitivity of galvanometer is \[=4\times {{10}^{-4}}A/div\] \[\therefore \]\[{{i}_{g}}=\] full scale deflection = current sensitivity x total number of turns \[=4\times {{10}^{-4}}\times 25=100\Omega \] The value of resistance required \[R=\frac{V}{{{i}_{g}}}-G=\frac{2.5}{{{10}^{-2}}}-100\] \[=250-100=150\Omega \]


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