A) \[\frac{M{{B}_{H}}\theta }{l}\]
B) \[\frac{l{{B}_{H}}\theta }{M}\]
C) \[\frac{M\theta }{l{{B}_{H}}}\]
D) \[\frac{l\theta }{M{{B}_{H}}}\]
Correct Answer: A
Solution :
If \[\alpha \] is the angular acceleration produced, then \[l\alpha =M{{B}_{H}}\sin \theta \] lf \[\theta \]is small, then \[\sin \theta \approx \theta \]and hence the angular acceleration is given by\[\alpha =\frac{M{{B}_{H}}\theta }{l}\]
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