A) 1
B) 4
C) 3
D) 2
Correct Answer: D
Solution :
The magnitude of electric field at an axial point Mat a distance z from the origin is given by \[\left| {{E}_{z}} \right|=\frac{1}{4\pi {{\varepsilon }_{0}}}.\frac{2pz}{{{({{z}^{2}}-{{a}^{2}})}^{2}}}\] For\[z>>a,\left| {{E}_{z}} \right|=\frac{2p}{4\pi {{\varepsilon }_{0}}{{z}^{3}}}\] and, magnitude of electric field at a equatorial point N at a distance y from origin (0,0) is given by For \[\left| {{E}_{y}} \right|=\frac{p}{4\pi {{\varepsilon }_{0}}{{({{y}^{2}}-{{a}^{2}})}^{3/2}}}\] For\[y>>a,\left| {{E}_{y}} \right|=\frac{1}{4\pi {{\varepsilon }_{0}}}.\frac{p}{{{y}^{3}}}\] For\[z=y>>a\therefore \left| \frac{{{E}_{y}}}{{{E}_{y}}} \right|=2\]You need to login to perform this action.
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