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VMMC VMMC Medical Solved Paper-2014

  • question_answer
    In and L-R circuit, the value of L is \[\left( \frac{0.4}{\pi } \right)\]H and the value of R is \[30\Omega .\]If in the circuit an alternating emf of 200 V at 50 cycle/s is connected, the impedances of the circuit and current will be

    A) \[11.4\Omega ,17.5A\]                 

    B) \[30.1\Omega ,6.5A\]

    C) \[40.4\Omega ,5A\]                       

    D) \[50\Omega ,4A\]

    Correct Answer: D

    Solution :

    Sol.         (d) Given,\[{{X}_{L}}=\omega L=2\pi fL\] \[=2\pi \times 50\times \frac{0.4}{\pi }=40\Omega \] \[R=30\,\Omega \] \[Z=\sqrt{{{R}^{2}}+X_{L}^{2}}\] \[=\sqrt{{{(30)}^{2}}+{{(40)}^{2}}}=50\Omega \] \[{{i}_{rms}}=\frac{{{V}_{rms}}}{Z}\] \[=\frac{200}{50}=4A\]


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