A) 10 N,11 N
B) 10 N, 6N
C) 10 N, 10 N
D) can't be calculated due to insufficient data
Correct Answer: C
Solution :
As shown in figure. (ii) \[{{T}_{1}}\cos {{30}^{o}}={{T}_{2}}\cos {{30}^{o}}\] \[\therefore \]\[{{T}_{1}}={{T}_{2}}=T\] (Let) Again\[{{T}_{1}}\sin {{30}^{o}}+{{T}_{2}}\sin {{30}^{o}}=10\]and\[2T\sin {{30}^{o}}=10\]\[2T.\frac{1}{2}=10\Rightarrow T=10N\] Thus, the tension in section BC and BF are 10 N and 10 N respectively.You need to login to perform this action.
You will be redirected in
3 sec