A) 2gh
B) mgh
C) \[\sqrt{2gh}\]
D) \[\frac{gh}{2}\]
Correct Answer: C
Solution :
From law of conservation of energy PE at A = KE at B or \[mgh=\frac{1}{2}m{{v}^{2}}\]or\[v=\sqrt{2gh}\]You need to login to perform this action.
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