A) \[\frac{{{k}_{1}}}{{{k}_{2}}}\]
B) \[\sqrt{\frac{{{k}_{1}}}{{{k}_{2}}}}\]
C) \[\frac{{{k}_{2}}}{{{k}_{1}}}\]
D) \[\sqrt{\frac{{{k}_{2}}}{{{k}_{1}}}}\]
Correct Answer: D
Solution :
Maximum velocities are equal. Hence,\[{{a}_{1}}{{\omega }_{1}}={{a}_{2}}{{\omega }_{2}}\] \[\frac{{{a}_{1}}}{{{a}_{2}}}=\frac{{{\omega }_{2}}}{{{\omega }_{1}}}\] \[=\frac{2\pi /{{n}_{2}}}{2\pi /{{n}_{1}}}\] \[=\frac{{{n}_{1}}}{{{n}_{2}}}\] \[=\frac{{{T}_{2}}}{{{T}_{1}}}=\frac{2\pi \sqrt{\frac{m}{{{k}_{1}}}}}{2\pi \sqrt{\frac{m}{{{k}_{2}}}}}=\sqrt{\frac{{{k}_{2}}}{{{k}_{1}}}}\]You need to login to perform this action.
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