A) NaCI
B) \[N{{a}_{2}}S\]
C) \[{{(N{{H}_{4}})}_{3}}P{{O}_{4}}\]
D) \[{{K}_{2}}S{{O}_{4}}\]
Correct Answer: A
Solution :
Flocculation value \[\propto \frac{1}{\text{coagulating}\,\text{power}}\]Among the given electrolytes, NaCI has lowest coagulating power so, its flocculation value will be maximum.
You need to login to perform this action.
You will be redirected in
3 sec
