A) \[XeO{{F}_{4}}\]
B) \[Ne{{F}_{2}}\]
C) \[Xe{{F}_{2}}\]
D) \[Xe{{F}_{6}}\]
Correct Answer: B
Solution :
\[Ne{{F}_{2}}\]does not exist due to very high ionization enthalpy \[(2080\,kJ\,mo{{l}^{-1}})\]of neon (Ne). Ionisation enthalpy of xenon is low \[(1170\,kJ\,mo{{l}^{-1}})\] so, its compounds like \[XeO{{F}_{4}},Xe{{F}_{2}},Xe{{F}_{6}}\] etc. exist.
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