A) 14.29%
B) 20.52%
C) 50.05%
D) 80%
Correct Answer: A
Solution :
Ammonium dichromate is \[{{(N{{H}_{4}})}_{2}}C{{r}_{2}}{{O}_{7}}.\] Number of parts by weight of cation, i.e., \[NH_{4}^{+}=2\times (14+4)=36\] % of\[NH_{4}^{+}=\frac{36\times 100}{252}=14.29%\]
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