A) \[Xe{{F}_{2}}.lF_{2}^{-}\]
B) \[B{{F}_{3}}.N{{H}_{3}}\]
C) \[C{{F}_{4}},S{{F}_{4}}\]
D) \[PC{{l}_{5}},lC{{l}_{5}}\]
Correct Answer: A
Solution :
Both \[Xe{{F}_{2}}\] and \[IF_{2}^{-}\] are linear species but the central atom Xe and I undergo \[s{{p}^{3}}d\] hybridization with all the three equatorial positions occupied by the lone pairs of electrons.
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