A) 0.80V
B) 0.208V
C) 0.37V
D) 0.18V
Correct Answer: B
Solution :
\[AgCl(s)A{{g}^{+}}(aq)+C{{l}^{-}}(aq)\] \[{{K}_{sp}}=[A{{g}^{+}}][C{{l}^{-}}]\] \[A{{g}^{+}}=\frac{{{K}_{sp}}}{[C{{l}^{-}}]}=\frac{1\times {{10}^{-10}}}{1}=1\times {{10}^{-10}}M\] \[A{{g}^{+}}+{{e}^{-}}\xrightarrow[{}]{{}}Ag\] \[E={{E}^{o}}-\frac{0.0591}{1}\log \frac{1}{1\times {{10}^{-10}}}\] \[=0.799-0.591=0.208V\]You need to login to perform this action.
You will be redirected in
3 sec