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VMMC VMMC Medical Solved Paper-2014

  • question_answer
    Knowing that \[{{K}_{sp}}\]for AgCl is \[1.0\times {{10}^{-10}}.\]Calculate E for \[A{{g}^{+}}/Ag\] electrode immersed in M KCl at 25° C.\[(E_{A{{g}^{+}}/Ag}^{o}=0.79V)\]

    A) 0.80V                    

    B) 0.208V

    C) 0.37V                    

    D) 0.18V

    Correct Answer: B

    Solution :

    \[AgCl(s)A{{g}^{+}}(aq)+C{{l}^{-}}(aq)\] \[{{K}_{sp}}=[A{{g}^{+}}][C{{l}^{-}}]\] \[A{{g}^{+}}=\frac{{{K}_{sp}}}{[C{{l}^{-}}]}=\frac{1\times {{10}^{-10}}}{1}=1\times {{10}^{-10}}M\] \[A{{g}^{+}}+{{e}^{-}}\xrightarrow[{}]{{}}Ag\] \[E={{E}^{o}}-\frac{0.0591}{1}\log \frac{1}{1\times {{10}^{-10}}}\] \[=0.799-0.591=0.208V\]


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