A) 1.0
B) 0.5
C) 1.5
D) 2.0
Correct Answer: B
Solution :
When benzoic acid dissolve in benzene it will be dimerise due to the intermolecular H-bonding. \[2{{C}_{6}}{{H}_{5}}COOH\xrightarrow[{}]{benzene}{{({{C}_{6}}{{H}_{5}}COOH)}_{2}}\]van?t Hoff factor\[=\frac{\text{no}\text{. of particles after association}}{\text{no}\text{. of particles before association}}=\frac{1}{2}=0.5\]
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