A) \[[M{{L}^{2}}{{T}^{-3}}{{A}^{-1}}]\]
B) \[[M{{L}^{2}}{{T}^{-2}}]\]
C) \[[M{{L}^{2}}{{T}^{-1}}{{A}^{-1}}]\]
D) \[[M{{L}^{2}}{{T}^{-3}}{{A}^{-2}}]\]
Correct Answer: D
Solution :
Resistance\[\text{R=}\frac{\text{Potential difference}}{\text{Current}}=\frac{Y}{l}=\frac{W}{ql}\] So, dimensions of R \[\text{=}\frac{\left[ \text{Dimensions of work} \right]}{\left[ \text{Dimensions of charge} \right]\text{ }\left[ \text{Dimensions of current} \right]}\]\[\text{=}\frac{[M{{L}^{2}}{{T}^{-2}}]}{[AT][A]}=[M{{L}^{2}}{{T}^{-3}}{{A}^{-2}}]\]
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