The relationship between the force F and position a: of a body is as shown in figure. The work done in displacing the body from x = 1 m to x = 5 m will be
A)30 J
B)15 J
C)25 J
D)20 J
Correct Answer:
D
Solution :
Work done = area enclosed by F-x graph. = area of OAM + area of ABNM + area of CDEN area of EFGH + area of HIJ \[=\frac{1}{2}\times 1\times 10+1\times 10+1\times 5-1\times 5+\frac{1}{2}\times 1\times 10\] \[=5+10+5-5+5=20J\]