A) predominantly-2-butyne
B) predominantly-1-butene
C) predominantly-2-butene
D) equimolar mixture of 1 and 2 butene
Correct Answer: C
Solution :
\[C{{H}_{3}}C{{H}_{3}}\underset{\begin{smallmatrix} | \\ Br \end{smallmatrix}}{\mathop{C}}\,HC{{H}_{3}}\to C{{H}_{3}}C{{H}_{2}}\overset{+}{\mathop{C}}\,HC{{H}_{3}}\xrightarrow[{}]{-{{H}^{+}}}\]\[\underset{\begin{smallmatrix} less\,substituted \\ \,\,\,\,\,\,\,\,\,\,\,\,\,\,(II) \end{smallmatrix}}{\mathop{C{{H}_{3}}C{{H}_{2}}CH=C{{H}_{2}}}}\,\underset{\begin{smallmatrix} more\,\,substituted \\ \,\,\,\,\,\,\,\,\,\,\,\,\,\,(I) \end{smallmatrix}}{\mathop{+C{{H}_{3}}CH=CHC{{H}_{3}}}}\,\] Stability of I > II, hence' (I) is predominant product.
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