A) \[N{{H}_{2}}CONH.N{{H}_{2}}HCl\]
B) \[N{{H}_{2}}N{{H}_{2}}.HCl\]
C) \[N{{H}_{2}}CON{{H}_{2}}\]
D) \[{{C}_{6}}{{H}_{5}}NHN{{H}_{2}}.HCl\]
Correct Answer: B
Solution :
\[N{{H}_{2}}-N{{H}_{2}}.HCl\] contains nitrogen but it does not contain carbon thus NaCN is not formed and test of nitrogen is negative.
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