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VMMC VMMC Medical Solved Paper-2014

  • question_answer
    The ionisation constant of ammonium hydroxide is \[1.77\times {{10}^{-5}}\] at 298 K. Hydrolysis constant of ammonium chloride is

    A) \[6.50\times {{10}^{-12}}\]                         

    B) \[5.56\times {{10}^{-13}}\]

    C) \[5.65\times {{10}^{-12}}\]                         

    D) \[5.65\times {{10}^{-10}}\]

    Correct Answer: D

    Solution :

    \[{{K}_{h}}=\frac{{{K}_{w}}}{{{K}_{b}}}=\frac{1\times {{10}^{-14}}}{1.77\times {{10}^{-5}}}=5.65\times {{10}^{-10}}\]


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