A) \[<1.2\times {{10}^{-2}}\]
B) \[>1.2\times {{10}^{-2}}\]
C) \[1.2\times {{10}^{-2}}\]
D) \[0.12\times {{10}^{-2}}\]
Correct Answer: A
Solution :
\[\Delta {{n}_{g}}=\] moles of gaseous products - moles of gaseous reactants, = 3 ? 2 ? 1 = 0 \[{{K}_{p}}={{K}_{c}}{{(RT)}^{\Delta {{n}_{g}}}}\] \[{{K}_{c}}=\frac{{{K}_{p}}}{RT}\] \[=\frac{1.2\times {{10}^{-2}}}{0.0821\times 1338}\] \[=1.09\times {{10}^{-4}}<1.2\times {{10}^{-2}}\]
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