A) 400
B) 300
C) 200
D) 150
Correct Answer: C
Solution :
\[{{r}_{0}}=1600={{\lambda }_{0}}{{N}_{0}}\] \[\frac{{{N}_{0}}}{N}=\frac{1600}{100},\]when t = 8 \[{{r}_{8}}=100=\lambda .N\]\[8=\frac{2.303}{\lambda }\log \frac{1600}{100}\] \[{{r}_{3}}=100=\lambda .N\]or\[\lambda =0.3466\] now\[{{r}_{0}}=1600\Rightarrow {{r}_{6}}=?t=6\] \[6=\frac{2.303}{\lambda }\log \frac{1600}{{{r}_{6}}}\]\[\therefore \]\[{{r}_{6}}=200\]
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