A) 300,225
B) 225,375
C) 375, 225
D) 225, 300
Correct Answer: B
Solution :
For ideal gas, \[\Delta E=n{{C}_{v}}.\Delta T=1\times \left( \frac{3}{2}\times 2 \right)\times (100-25)=225cal\]Now,\[{{C}_{p}}={{C}_{v}}+R=\frac{3}{2}R+R=\frac{5}{2}R\] \[\Delta E=n{{C}_{p}}\Delta T=1\times \left( \frac{5}{2}\times 2 \right)\times (100-25)=375cal\]You need to login to perform this action.
You will be redirected in
3 sec