A) \[4.2\times {{10}^{4}}\]
B) \[4.2\times {{10}^{8}}\]
C) \[3.0\times {{10}^{5}}\]
D) \[2.6\times {{10}^{6}}\]
Correct Answer: C
Solution :
Given intensity, \[I={{10}^{-9}}Wb{{m}^{-2}}\] \[={{10}^{-9}}J{{s}^{-1}}{{m}^{-2}}\] If the number of photons are n, then \[\frac{nhv}{{{10}^{-5}}}={{10}^{-9}}\]\[\Rightarrow \]\[\frac{nhc}{\lambda \times {{10}^{-5}}}={{10}^{-9}}\] \[\Rightarrow \]\[\frac{n\times 6.6\times {{10}^{-34}}\times 3\times {{10}^{8}}}{600\times {{10}^{-9}}\times {{10}^{-5}}}={{10}^{-9}}\] \[3.3n\times {{10}^{-14}}={{10}^{-9}}\] \[n=\frac{{{10}^{-9}}}{3.3\times {{10}^{-14}}}\] \[=0.303\times {{10}^{5}}\] \[=303\times {{10}^{4}}\]
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