VMMC VMMC Medical Solved Paper-2015

  • question_answer
    A parallel beam of a monochromatic light of wavelength 900 nm passes through a long slit of width 0.4 mm. The angular divergence in which most of the light is diffracted, is

    A) \[4.5\times {{10}^{-3}}\]rad       

    B) \[9.0\times {{10}^{-3}}\]rad

    C) \[2.25\times {{10}^{-3}}\]rad     

    D) None of these

    Correct Answer: A

    Solution :

    Mostly, diffraction takes place between two first order minima. In case of minima, \[b\sin \theta =\pm \lambda \]\[\Rightarrow \]\[b\sin \theta =\pm \frac{900\times {{10}^{-9}}m}{0.4\times {{10}^{-3}}m}\] \[=\pm 2.25\times {{10}^{-3}}\]\[\Rightarrow \]\[\theta \approx 2.25\times {{10}^{-3}}rad.\] Therefore, the angular divergence. \[=4.5\times {{10}^{-3}}\]rad


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