A) 9
B) 7
C) 8
D) 11
Correct Answer: A
Solution :
Amplitude of light coming from narrower slit is A, then the amplitude of light coming from other slit will be 2A. Thus,\[{{A}_{\max }}=2A+A=3A\] In case of minimum intensity\[{{A}_{\min }}=2A-A=A\] The required ratio of intensities\[\frac{{{\operatorname{I}}_{max}}}{{{\operatorname{I}}_{min}}}=\frac{{{({{A}_{\max }})}^{2}}}{{{({{A}_{\min }})}^{2}}}\] \[=\frac{{{(3A)}^{2}}}{{{A}^{2}}}=9\]
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