VMMC VMMC Medical Solved Paper-2015

  • question_answer
    A partly hanging unifom chain of lenght L is resting on a rough horizontal table. I is the maximum possible length that can hung in equilibrium. The coefficient of friction between the chain and table is

    A) \[\frac{l}{L-l}\]                  

    B) \[\frac{L}{l}\]

    C) \[\frac{l}{L}\]                                    

    D) \[\frac{lL}{L+l}\]

    Correct Answer: C

    Solution :

    If \[\mu \]is the mass per unit length then weight of hanging length \[=\mu /g\] Weight of chain on table \[=\mu (L-1)g\] \[R=\mu (L-1)g\] \[f=\mu sR\] \[=\mu s.\mu (L-1)g\] \[{{\mu }_{s}}.\mu (L-1)g=\mu g\]\[\mu =\frac{l}{L-1}\]


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