A) Electron
B) Proton
C) Neutron
D) Neutrino
Correct Answer: D
Solution :
The nucleus formed is\[_{z}{{X}^{A}}\]. Applying conservation of mass number \[11=11+0+A\Rightarrow A=0\] Now, from conservation of charge \[6=5+1+Z\]\[\Rightarrow \]Z = 0 Thus, X is express as\[_{0}{{X}^{0}}\]and hence neutrinoYou need to login to perform this action.
You will be redirected in
3 sec