A) 700 J
B) 350 J
C) 175 J
D) 1050 J
Correct Answer: B
Solution :
Work done in an isobaric process \[W=p({{V}_{2}}-{{V}_{1}})\] \[W=nR{{V}_{2}}-nR{{V}_{1}}\]\[\Rightarrow \]\[{{T}_{2}}-{{T}_{1}}=\frac{W}{nR}\] The heat given in this process \[Q=n{{C}_{p}}({{T}_{2}}-{{T}_{1}})\] \[=n{{C}_{p}}\left( \frac{W}{nR} \right)=n\left( \frac{7}{2}R \right)\left( \frac{W}{nR} \right)\] \[=\frac{7}{2}W=\frac{7}{2}\times 100=350J\]
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