VMMC VMMC Medical Solved Paper-2015

  • question_answer
    The specific resistivity p of a circular wire of radius r, resistance R and length l is given by \[\rho \frac{\pi {{r}^{2}}R}{l}\]Given, \[r=(324\pm 0.02)cm\] \[R=(30\pm 1)\Omega \]and\[l=(4.80\pm 0.01)cm\] The percentage error in \[\rho \] is nearly

    A) 7%                                         

    B) 20%

    C) 18%                                       

    D) None of these

    Correct Answer: B

    Solution :

    Required percentage \[=\frac{2\times 0.02}{0.24}\times 100+\frac{1}{30}\times 100+\frac{0.01}{4.80}\times 100\] \[=16.7+3.3+0.2=20%\]


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