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VMMC VMMC Medical Solved Paper-2015

  • question_answer
    A galvanometer of resistance \[20\Omega \]shows a deflection of 10 divisions. When current of 1 mA is passed through it. If a shunt of \[4\Omega \] is connected and there are 50 divisions on the scale, the range of the galvanometer is

    A)  35 mA                 

    B) 40 mA

    C) 30 mA                  

    D) 25 mA

    Correct Answer: C

    Solution :

    Here, galvanometer current \[{{i}_{g}}=\frac{1mA}{10}\times 50=5mA\] \[S=4\Omega \]and\[G=20\Omega \] As, sheet\[S=\frac{{{i}_{g}}G}{i-{{i}_{g}}}\Rightarrow 4=\frac{5\times {{10}^{-3}}\times 20}{i-2\times {{10}^{-3}}}\] On solving, we get\[i=30\times {{10}^{-3}}=30mA\]


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