A) 2- methylpropan-2-ol > 2- butanol> 1- butanol
B) 2- methylpropan-2-ol > 1 - butanol> 2- butanol
C) 2- butanol> 2- methylpropan -2-ol > 1- butanol
D) 1 -butanol> 2-butanol > 2- methylpropan -2-ol
Correct Answer: A
Solution :
As both \[{{E}_{1}}\] and \[{{E}_{2}}\] elimination is preferred if leaving group is at 3° carbocation, then 2° carbon and then at 1° carbon. In case of 2-methylpropan-2-ol, 2-butanol and 1-butanol the leaving group \[{{H}_{3}}{{O}^{+}}\] is at 3°, 2° and 1° carbon respectively, so dehydration follows the order in given option (a).
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