2. Solved Papers
  3. VMMC

VMMC VMMC Medical Solved Paper-2015

  • question_answer
    Addition of 1.0 g of a compound to 10 g of water .increases the boiling point by 0.3°C. The amount of compound needed to prepare a 500 mL of 0.1 solution is [Given: assume negligible dissociation or association of the compound, boiling point constant \[{{k}_{b}}\] of water\[=0.513kg\,mo{{l}^{-1}}\]]

    A) 0.855 g                 

    B) 17.1 g

    C) 8.55 g                   

    D)  85.5 g

    Correct Answer: C

    Solution :

    \[\Delta {{T}_{b}}={{m}_{solute}}{{K}_{b}}\] \[=0.3=\frac{\left( \frac{1.0}{M} \right)\times 1000}{10}\times 0.513\] = 171 [M = molecular weight of solute] We have, Molarity \[\text{=}\frac{\frac{\text{Weight}}{\text{M}}\text{ }\!\!\times\!\!\text{ 1000}}{\text{Volume}\,\text{of}\,\text{solution(in}\,\text{mL)}}\] \[\text{0}\text{.1=}\frac{\frac{\text{Weight}}{171}\text{ }\!\!\times\!\!\text{ 1000}}{500}\]Weight = 5.55 g


You need to login to perform this action.
You will be redirected in 3 sec spinner