A) \[\frac{10_{y}^{3}}{2({{x}_{1}}+{{x}_{2}}-2{{x}_{3}})}\]
B) \[\frac{{{10}^{6}}{{y}^{2}}}{{{(x+{{x}_{2}}-2{{x}_{3}})}^{2}}}\]
C) \[\frac{{{10}^{6}}{{y}^{2}}}{4{{({{x}_{1}}+{{x}_{2}}-2{{x}_{3}})}^{2}}}\]
D) \[\frac{{{x}_{1}}+{{x}_{2}}-2{{x}_{3}}}{{{10}^{6}}{{y}^{2}}}\]
Correct Answer: C
Solution :
\[{{\Alpha }_{BaS{{O}_{4}}}}={{\Alpha }_{BaC{{l}_{2}}}}+{{\Alpha }_{{{H}_{2}}S{{O}_{4}}}}-2\times {{\Alpha }_{HCl}}\] \[={{x}_{1}}+{{x}_{2}}-2{{x}_{3}}\] \[{{\Alpha }_{BaS{{O}_{4}}}}=\frac{1000\times k}{\text{Normality}}\] \[\text{Molarity}=\frac{{{10}^{3}}\times y}{{{x}_{1}}+{{x}_{2}}-2{{x}_{3}}}\] For \[\text{BaS}{{\text{O}}_{\text{4}}}\text{,}{{\text{K}}_{\text{sp}}}={{s}^{2}}-{{\left[ \frac{{{10}^{3}}\times y}{2({{x}_{1}}+{{x}_{2}}-2{{x}_{3}})} \right]}^{2}}\] \[\frac{{{10}^{6}}\times {{y}^{2}}}{4{{({{x}_{1}}+{{x}_{2}}-2{{x}_{3}})}^{2}}}\]
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