A) 33%
B) 66%
C) 70%
D) 40%
Correct Answer: B
Solution :
Meq. of oxalate = Meq. of \[KMn{{O}_{4}}\] \[\frac{w}{88/2}\times 1000=90\frac{1}{20}\] \[\therefore \]w oxalate ion = 0.198 g \[\therefore \]of oxalate ion \[=\frac{0.198}{0.3}\times 100=66%\]You need to login to perform this action.
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