A) \[{{R}_{3}}Si-O-Si{{R}_{3}}\]
B) \[{{(-{{R}_{3}}Si-O-Si{{R}_{3}}-)}_{n}}\]
C) \[{{R}_{3}}SiOH\]
D) \[-\underset{\underset{-\underset{\text{ }\!\!|\!\!\text{ }}{\overset{\text{ }\!\!|\!\!\text{ }}{\mathop{\text{Si}}}}\,-\text{O}}{\overset{|}{\mathop{\text{O}}}}\,}{\overset{\begin{smallmatrix} \text{R} \\ | \end{smallmatrix}}{\mathop{\text{Si}}}}\,-\text{O}-\underset{\underset{-\underset{|}{\overset{|}{\mathop{\text{Si}}}}\,-}{\overset{|}{\mathop{\text{O}}}}\,}{\overset{\begin{smallmatrix} \text{R} \\ | \end{smallmatrix}}{\mathop{\text{Si}}}}\,-\]
Correct Answer: A
Solution :
\[{{R}_{3}}SiCl\] on hydrolysis can only form a dimer. \[{{R}_{3}}SiCl\xrightarrow[{}]{{{H}_{2}}O}{{R}_{3}}SiOH\] \[{{R}_{3}}SiOH+{{R}_{3}}SiOH\xrightarrow[{}]{-{{H}_{2}}O}{{R}_{3}}Si-O-Si{{R}_{3}}\]
You need to login to perform this action.
You will be redirected in
3 sec
