2. Solved Papers
  3. VMMC

VMMC VMMC Medical Solved Paper-2015

  • question_answer
    The work done during the free expension of  1 mole of an ideal gas at 27°C is twice of its original volume is Given \[RT=2494\,\text{J mo}{{\text{l}}^{\text{-1}}}\text{(ln}2=0.7,\log 2=0.3)\]

    A) \[1746\,\text{J mo}{{\text{l}}^{\text{-1}}}\]                       

    B) \[-1746\,\text{J mo}{{\text{l}}^{\text{-1}}}\]

    C) zero                                      

    D) \[748.2\,\text{J mo}{{\text{l}}^{\text{-1}}}\]

    Correct Answer: C

    Solution :

    Work done \[=\int\limits_{{{V}_{0}}}^{2{{V}_{0}}}{{{p}_{ex}}dV=0}\] [\[\because \] In free expansions, \[{{p}_{ex}}=0\]]


You need to login to perform this action.
You will be redirected in 3 sec spinner