question_answer

The correct order of dipole moments \[(\mu )\]of the following compounds, is 1.\[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}CHO\] 2.\[C{{H}_{3}}CH=CH-CHO\] 3.\[C{{H}_{3}}C{{H}_{2}}CH=C{{H}_{2}}\]

A) \[{{\mu }_{1}}>{{\mu }_{2}}>{{\mu }_{3}}\]        

B) \[{{\mu }_{2}}>{{\mu }_{3}}>{{\mu }_{1}}\]

C) \[{{\mu }_{3}}>{{\mu }_{1}}>{{\mu }_{2}}\]        

D) \[{{\mu }_{2}}>{{\mu }_{1}}>{{\mu }_{3}}\]

Correct Answer: D

Solution :

As bond has larger dipole moment than so both \[{{\mu }_{1}}\] and \[{{\mu }_{2}}\]will be larger then \[{{\mu }_{3}}.\]