A) 74.89 cm
B) 67.62 cm
C) 88.67 cm
D) 42.70 cm
Correct Answer: A
Solution :
From the formula for the linear expansion, the length at 30°C is given as\[{{l}_{\theta }}=75[1+\alpha (30)]\]...(i) At this temperature suppose the length of mercury column is \[{{l}_{0}}\] while its length at 0°C is \[{{l}_{0}},\] then\[{{l}_{\theta }}={{l}_{0}}\left[ 1+\frac{1}{3}\gamma (30) \right]\] ...(ii) From Eqs. (i) and (ii), we get \[{{l}_{0}}\left[ 1+\frac{1}{3}\gamma (30) \right]=75[1+\alpha (30)]\]\[\Rightarrow \]\[{{l}_{0}}=7489cm\]You need to login to perform this action.
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