A) R
B) 2R
C) \[\frac{3R}{5}\]
D) 4R
Correct Answer: A
Solution :
The figure can be rearranged as, As,\[\frac{\text{resistance across AP}}{\text{resistance across AQ}}\] \[=\frac{\text{resistance across PB}}{\text{resistance across QB}}\]\[\Rightarrow \]\[\frac{R}{R}=\frac{R}{R}=1\] It shows the balance conduction of Wheatstone bridge. So, the current through arm PQ is zero. The effective resistance between A and B. \[{{\operatorname{R}}_{eff}}\frac{2R\times 2R}{2R+2R}=\frac{2R}{2}=R\]You need to login to perform this action.
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