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VMMC VMMC Medical Solved Paper-2015

  • question_answer
    The ionic radii of \[C{{a}^{2+}}\] and \[{{F}^{-}}\]are 100 pm and 133 pm respectively. The coordination number of \[C{{a}^{2+}}\] in the ionic solid will be

    A) 8                                             

    B) 6

    C) 4                                             

    D) 2

    Correct Answer: A

    Solution :

    Radius \[ratio=\frac{{{r}_{C{{a}^{2+}}}}}{{{r}^{F-}}}=\frac{100pm}{133pm}=0.75\] As,\[\text{0}\text{.73}\,\text{}\frac{{{\text{r}}_{\text{cation}}}}{{{\text{r}}_{\text{anion}}}}.\] So, coordination number of cation = 8


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