A) 100.75°C
B) 100.5°C
C) 100°C
D) 100.25°C
Correct Answer: D
Solution :
\[\Delta {{T}_{b}}=\frac{{{K}_{b}}\times 1000\times {{W}_{B}}}{{{W}_{A}}\times {{M}_{B}}}\] Since, \[{{K}_{b}}\]and \[{{W}_{A}}\]are same for two solutions, \[\frac{\Delta {{T}_{b}}}{\Delta {{T}_{b}}}=\frac{{{W}_{B}}\times M{{'}_{B}}}{W{{'}_{B}}\times {{M}_{B}}}\] \[\Delta {{T}_{b}}\text{(Urea)}={{0.25}^{o}},{{W}_{B}}=1g,{{M}_{B}}=60\] \[\Delta T{{'}_{b}}\text{(Glucose)}=?,W{{'}_{B}}=3g,M{{'}_{B}}=180\] \[\therefore \]\[\frac{0.25}{\Delta T{{'}_{b}}}=\frac{1\times 180}{3\times 60}\]\[\Delta {{T}_{b}}={{0.25}^{o}}C\] \[\therefore \]Boiling point of solution = 100 + 0.25 = 100.25°C (solutions of non-electrolyte having same concentrations will boil at same temperature)
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