A) \[k=k'\]
B) \[k'=2k\]
C) \[k'=\frac{1}{2}k\]
D) \[k>k'\]
Correct Answer: B
Solution :
\[2{{N}_{2}}{{O}_{5}}(g)\xrightarrow[{}]{{}}4N{{O}_{2}}+{{O}_{2}}(g)\] Rate\[=-\frac{1}{2}\frac{[{{N}_{2}}{{O}_{5}}]}{dt}=k[{{N}_{2}}{{O}_{5}}]\] or Rate\[=-\frac{d[{{N}_{2}}{{O}_{5}}]}{dt}=2k[{{N}_{2}}{{O}_{5}}]\] For\[{{N}_{2}}{{O}_{5}}\xrightarrow[{}]{{}}2N{{O}_{2}}+\frac{1}{2}{{O}_{2}}\] \[-\frac{d[{{N}_{2}}{{O}_{5}}]}{dt}=k'[{{N}_{2}}{{O}_{5}}]\] or Rate\[=-\frac{d[{{N}_{2}}{{O}_{5}}]}{dt}=k'[{{N}_{2}}{{O}_{5}}]\] Since, rate must be .same, k' = 2k
You need to login to perform this action.
You will be redirected in
3 sec
