A) \[\frac{1}{G}\]
B) \[\frac{1}{{{G}^{2}}}\]
C) \[G\]
D) \[{{G}^{2}}\]
Correct Answer: A
Solution :
Voltage sensitivity \[=\frac{Q}{V}\] Current sensitivity \[=\frac{Q}{I}\] Also, potential difference, \[V=IG\] Hence, \[\frac{{{V}_{S}}}{{{I}_{S}}}=\frac{Q/V}{Q/I}=\frac{I}{V}=\frac{I}{IG}\] \[\therefore \] \[\frac{{{V}_{S}}}{{{I}_{S}}}=\frac{1}{G}\]You need to login to perform this action.
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