A) 1
B) 2
C) 5
D) 6
Correct Answer: C
Solution :
From Biot-savart law the magnetic field at the centre is directly proportional to the length of current carrying segment. \[\therefore \] \[\frac{{{B}_{1}}}{{{B}_{2}}}=\frac{\text{length}\,\text{of}\,\text{ABC}}{\text{length}\,\text{of}\,\text{ADC}}\] \[\text{=}\frac{\text{angle}\,\text{subtended}\,\text{by}\,\text{ABC}}{\text{angle}\,\text{subtended}\,\text{by}\,\text{AD}\text{C}}\] \[=\frac{({{360}^{o}}-{{60}^{o}})}{{{60}^{o}}}=\frac{300}{60}=\frac{5}{1}\]You need to login to perform this action.
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