A) 229
B) 458
C) 689
D) 916
Correct Answer: B
Solution :
Current in coil of tangent galvanometer \[i=\frac{2rH}{{{\mu }_{0}}n}\tan \theta \] \[\Rightarrow \] \[n=\frac{2rH}{{{\mu }_{0}}i}\tan \theta \] \[\therefore \] \[n=\frac{2\times 16\times {{10}^{-2}}\times 0.36\times {{10}^{-4}}}{4\pi \times {{10}^{-7}}\times 20\times {{10}^{-3}}}\tan {{45}^{o}}\] \[=458\]You need to login to perform this action.
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