A) 1 A
B) 0.5 A
C) 0.2A
D) 0.1A
Correct Answer: D
Solution :
Induced emf, \[|e|=L\frac{di}{dt}\] \[=(60\times {{10}^{-3}})\times \frac{(1.5-1)}{0.1}\] \[=\frac{60\times {{10}^{-3}}\times 0.5}{0.1}=0.3\,V\] Induced current, \[i=\frac{e}{R}=\frac{0.3}{3}=0.1A\]You need to login to perform this action.
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