A) \[1.27\text{ }\overset{\text{o}}{\mathop{\text{A}}}\,\]
B) \[0.17\text{ }\overset{\text{o}}{\mathop{\text{A}}}\,\]
C) \[0.57\text{ }\overset{\text{o}}{\mathop{\text{A}}}\,\]
D) \[0.99\text{ }\overset{\text{o}}{\mathop{\text{A}}}\,\]
Correct Answer: B
Solution :
The radius of hydrogen atom \[=0.53\overset{\text{o}}{\mathop{\text{A}}}\,\] \[{{\,}_{\text{3}}}\text{L}{{\text{i}}^{\text{+2}}}\] ion also has only one electron but it has 3 protons in nucleus, hence its electron fells three times more attraction from nucleus in comparison of hydrogen atom. Thus, the radius of \[{{\,}_{\text{3}}}\text{L}{{\text{i}}^{\text{+2}}}\] will be\[=\frac{0.53}{3}=0.17\overset{\text{o}}{\mathop{\text{A}}}\,\]
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